题目内容
计算:
(1)6(2ab+3a)-7(4a-ab)
(2)5x2-[12x-(
x-6)+4x]
(3)18-[25-(-7)-(-4)]+22-33
(4)|-7
|×(
-
)÷
-
÷(-
)
(5)21°44′÷4
(6)15°24′+32°47′-6°55′.
(1)6(2ab+3a)-7(4a-ab)
(2)5x2-[12x-(
| 1 |
| 3 |
(3)18-[25-(-7)-(-4)]+22-33
(4)|-7
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 5 |
| 12 |
| 9 |
| 2 |
| 3 |
| 2 |
(5)21°44′÷4
(6)15°24′+32°47′-6°55′.
(1)原式=12ab+18a-28a+7ab=19ab-10a;
(2)原式=5x2-12x+(
x-6)-4x=5x2-
x-6;
(3)原式=18-(25+7+4)+4-27=18-36+4-27=-41;
(4)原式=
×(-
)×
-
×(-
)=-3+3=0;
(5)原式=5°26′;
(6)原式=41°16′.
(2)原式=5x2-12x+(
| 1 |
| 3 |
| 47 |
| 3 |
(3)原式=18-(25+7+4)+4-27=18-36+4-27=-41;
(4)原式=
| 15 |
| 2 |
| 1 |
| 6 |
| 12 |
| 5 |
| 9 |
| 2 |
| 2 |
| 3 |
(5)原式=5°26′;
(6)原式=41°16′.
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