题目内容
先化简,再求值:| x2+1 |
| x2-1 |
| x-2 |
| x-1 |
| x-2 |
| x |
分析:这道求代数式值的题目,不应考虑把x的值直接代入,通常做法是先把除法转换为乘法化简,然后进行减法运算,最后代入求值.
解答:解:原式=
-
•
=
-
(2分)
=
(4分)
=
=-
.(6分)
∴当x=-3时,原式=-
=
.(8分)
| x2+1 |
| x2-1 |
| x-2 |
| x-1 |
| x |
| x-2 |
=
| x2+1 |
| (x+1)(x-1) |
| x |
| x-1 |
=
| x2+1-x(x+1) |
| (x+1)(x-1) |
=
| 1-x |
| (x+1)(x-1) |
=-
| 1 |
| x+1 |
∴当x=-3时,原式=-
| 1 |
| -3+1 |
| 1 |
| 2 |
点评:本题主要考查分式的化简求值,分子、分母能因式分解的先因式分解;除法要统一为乘法运算.
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