题目内容
先化简,再求值:
÷y3,其中x=-11,y=
.
| y3-y |
| (xy+1)2-(x+y)2 |
| 1 |
| 12 |
分析:先进行因式分解,再把除法转化成乘法,再进行约分,把分式化到最简,然后把x,y的值代入计算即可.
解答:解:
÷y3=
×
=
=
=
=
,
把x=-11,y=
代入上式得,
原式=
=
.
| y3-y |
| (xy+1)2-(x+y)2 |
| y(y2-1) |
| x2y2-x2-y2+1 |
| 1 |
| y3 |
| (y+1)(y-1) |
| x2y4-x2y2-y4-y2 |
| (y+1)(y-1) |
| y2[x2(y2-1)-(y2-1)] |
| (y+1)(y-1) |
| y2[(x2-1)(y2-1)] |
| 1 |
| y2(x2-1) |
把x=-11,y=
| 1 |
| 12 |
原式=
| 1 | ||
(
|
| 6 |
| 5 |
点评:此题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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