ÌâÄ¿ÄÚÈÝ

ÀîÁÁ¡¢Íõ³ÉÁ½Î»Í¬Ñ§°ËÄê¼¶5´ÎÊýѧµ¥Ôª×ÔÎÒ¼ì²âµÄ³É¼¨£¬ÈçϱíËùʾ£º
5´ÎÊýѧµ¥Ôª×ÔÎÒ¼ì²âµÄ³É¼¨ ƽ¾ùÊý ·½²î
ÀîÁÁ 80 70 90 70 90 80·Ö £¿
Íõ³É 70 90 100 90 50 80·Ö 320·Ö2
£¨1£©ÇóÀîÁÁµÄ·½²îÊǶàÉÙ£¿Æ½Ê±Ë­µÄ³É¼¨±È½ÏÎȶ¨£¿
£¨2£©Èô5´ÎÊýѧµ¥Ôª³É¼¨µÄƽ¾ù·Ö×÷Ϊƽʱ³É¼¨£®ÀîÁÁµÄÆÚÖгɼ¨Îª85·Ö£¬ÆÚÄ©³É¼¨Îª80·Ö£»Íõ³ÉµÄÆÚÖгɼ¨Îª70·Ö£¬ÆÚÄ©³É¼¨90·Ö£®Èôƽʱ³É¼¨£¬ÆÚÖгɼ¨£¬ÆÚÄ©³É¼¨°´3£º3£º4µÄ±ÈÖØ×÷Ϊ×îÖÕµÄѧÆÚ³É¼¨£¬ÔòÀîÁÁ×îÖÕµÄѧÆÚ³É¼¨Îª81.5·Ö£¬ÇëÇó³öÍõ³É×îÖÕµÄѧÆÚ³É¼¨ÊǶàÉÙ·Ö£¿
·ÖÎö£º£¨1£©ÀûÓñí¸ñÒÔ¼°·½²î¹«Ê½Ö±½ÓÇó³öÀîÁÁµÄ·½²î¼´¿É£¬½ø¶øÀûÓ÷½²îԽСԽÎȶ¨£¬µÃ³ö´ð°¸¼´¿É£»
£¨2£©ÀûÓüÓȨƽ¾ùÊýÇó·¨Ö±½ÓµÃ³öÍõ³É×îÖÕµÄѧÆÚ³É¼¨¼´¿É£®
½â´ð£º½â£º£¨1£©¡ßƽ¾ùÊýΪ80£¬
¡à
S
2
ÀîÁÁ
=
1
5
[£¨80-80£©2+£¨70-80£©2+£¨90-80£©2+£¨70-80£©2+£¨90-80£©2]
=
1
5
¡Á400
=80£¬
¡ß320£¾80£¬
¡àƽʱÀîÁÁµÄ³É¼¨±È½ÏÎȶ¨£»

£¨2£©
80¡Á3+70¡Á3+90¡Á4
3+3+4
=81

´ð£ºÍõ³É×îÖÕµÄѧÆÚ³É¼¨ÊÇ81·Ö£®
µãÆÀ£º´ËÌâÖ÷Òª¿¼²éÁ˼ÓȨƽ¾ùÊý£¬·½²î£¬¹Ø¼üÊÇÕÆÎÕ·½²î¹«Ê½£¬S2=
1
n
[£¨x1-
.
x
£©2+£¨x2-
.
x
£©2+¡­+£¨xn-
.
x
£©2]£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø