题目内容
先化简,再求值:
-
÷
,其中x=
-2.
| 2x |
| x2-4 |
| x-2 |
| x |
| x2-4x+4 |
| x |
| 2 |
分析:先根据分式混合运算的法则把原式进行化简,再把x的值代入进行计算即可.
解答:解:原式=
-
×
=
-
=
-
=
=
=
,
当x=
-2时,原式=
=
=
=
.
| 2x |
| (x+2)(x-2) |
| x-2 |
| x |
| x |
| (x-2)2 |
=
| 2x |
| (x+2)(x-2) |
| 1 |
| x-2 |
=
| 2x |
| (x+2)(x-2) |
| x+2 |
| (x+2)(x-2) |
=
| 2x-x-2 |
| (x+2)(x-2) |
=
| x-2 |
| (x+2)(x-2) |
=
| 1 |
| x+2 |
当x=
| 2 |
| 1 |
| x+2 |
| 1 | ||
|
| 1 | ||
|
| ||
| 2 |
点评:本题考查的是分式的混合运算,熟知分式混合运算的法则是解答此题的关键.
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