ÌâÄ¿ÄÚÈÝ
³ö×⳵˾»úСÀîijÌìÉÏÎçÓªÔËʱÊÇÔÚ¶«Î÷×ßÏòµÄ´ó½ÖÉϽøÐеģ¬Èç¹û¹æ¶¨£ºÏò¶«ÎªÕý£¬ÏòÎ÷Ϊ¸º£¬ËûÕâÌìÉÏÎçËù½ÓÁùλ³Ë¿ÍµÄÐгµÀï³Ì£¨µ¥Î»£ºkm£©ÈçÏ£º-2£¬+5£¬-1£¬+1£¬-6£¬-2£¬ÎÊ£º
£¨1£©½«×îºóһλ³Ë¿ÍË͵½Ä¿µÄµØÊ±£¬Ð¡ÀîÔÚʲôλÖã¿
£¨2£©ÈôÆû³µºÄÓÍÁ¿Îª0.2L/km£¨Éý/ǧÃ×£©£¬ÕâÌìÉÏÎçСÀî½ÓËͳ˿ͣ¬³ö×â³µ¹²ºÄÓͶàÉÙÉý£¿
£¨3£©Èô³ö×â³µÆð²½¼ÛΪ8Ôª£¬Æð²½Àï³ÌΪ2.5km£¨°üÀ¨2.5km£©£¬³¬¹ý²¿·Ö£¨²»×ã1ǧÃ×°´1ǧÃ×¼ÆË㣩ÿǧÃ×1.5Ôª£¬ÎÊСÀîÕâÌìÉÏÎç¹²µÃ³µ·Ñ¶àÉÙÔª£¿
£¨1£©½«×îºóһλ³Ë¿ÍË͵½Ä¿µÄµØÊ±£¬Ð¡ÀîÔÚʲôλÖã¿
£¨2£©ÈôÆû³µºÄÓÍÁ¿Îª0.2L/km£¨Éý/ǧÃ×£©£¬ÕâÌìÉÏÎçСÀî½ÓËͳ˿ͣ¬³ö×â³µ¹²ºÄÓͶàÉÙÉý£¿
£¨3£©Èô³ö×â³µÆð²½¼ÛΪ8Ôª£¬Æð²½Àï³ÌΪ2.5km£¨°üÀ¨2.5km£©£¬³¬¹ý²¿·Ö£¨²»×ã1ǧÃ×°´1ǧÃ×¼ÆË㣩ÿǧÃ×1.5Ôª£¬ÎÊСÀîÕâÌìÉÏÎç¹²µÃ³µ·Ñ¶àÉÙÔª£¿
¿¼µã£ºÕýÊýºÍ¸ºÊý
רÌ⣺
·ÖÎö£º£¨1£©¼ÆËã³öÁù´ÎÐгµÀï³ÌµÄºÍ£¬¿´Æä½á¹ûµÄÕý¸º¼´¿ÉÅÐ¶ÏÆäλÖã»
£¨2£©Çó³öËù¼Ç¼µÄÁù´ÎÐгµÀï³ÌµÄ¾ø¶ÔÖµ£¬ÔÙ¼ÆËãºÄÓͼ´¿É£»
£¨3£©·Ö±ð¼ÆËãÃ¿Î»ÖØ³Ë¿ÍµÄ³µ·ÑÇóºÍ¼´¿É£®
£¨2£©Çó³öËù¼Ç¼µÄÁù´ÎÐгµÀï³ÌµÄ¾ø¶ÔÖµ£¬ÔÙ¼ÆËãºÄÓͼ´¿É£»
£¨3£©·Ö±ð¼ÆËãÃ¿Î»ÖØ³Ë¿ÍµÄ³µ·ÑÇóºÍ¼´¿É£®
½â´ð£º½â£º
£¨1£©-2+5-1+1-6-2=-5£¬
¹Ê´ËʱСÀîÔÚÏòÎ÷5Ã×µÄλÖã»
£¨2£©|-2|+|+5|+|-1|+|+1|+|-6|+|-2|=2+5+1+1+6+2=17£¨Ç§Ã×£©£¬
0.2¡Á17=3.4£¨Éý£©£¬
³ö×â³µ¹²ºÄÓÍ3.4Éý£»
£¨3£©¸ù¾ÝÌâÒâ¿ÉµÃ£º8+8+3.75+8+8+8+5.25+8=57£¨Ôª£©£¬
¼´Ð¡ÀîÕâÌìÉÏÎç¹²µÃ³µ·Ñ57Ôª£®
£¨1£©-2+5-1+1-6-2=-5£¬
¹Ê´ËʱСÀîÔÚÏòÎ÷5Ã×µÄλÖã»
£¨2£©|-2|+|+5|+|-1|+|+1|+|-6|+|-2|=2+5+1+1+6+2=17£¨Ç§Ã×£©£¬
0.2¡Á17=3.4£¨Éý£©£¬
³ö×â³µ¹²ºÄÓÍ3.4Éý£»
£¨3£©¸ù¾ÝÌâÒâ¿ÉµÃ£º8+8+3.75+8+8+8+5.25+8=57£¨Ôª£©£¬
¼´Ð¡ÀîÕâÌìÉÏÎç¹²µÃ³µ·Ñ57Ôª£®
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éÓÐÀíÊýµÄ¼Ó¼õÔËË㣬עÒâÕý¸ºÊýµÄÒâÒ壬ÊìÁ·ÕÆÎÕÔËËã·¨ÔòÊǽâÌâµÄ¹Ø¼ü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁÐͼÐÎÖУ¬ÊÇÔ²ÖܽǵÄÊÇ£¨¡¡¡¡£©
| A¡¢ |
| B¡¢ |
| C¡¢ |
| D¡¢ |