题目内容
先化简,再求值:
÷
•
,其中x=
.
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
| 1 |
| 2 |
分析:先把要求的式子因式分解,然后约分,再把x的值代入即可.
解答:解:
÷
•
=
×
•
=
,
把x=
代入上式得:
原式=
=
.
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
=
| (x+1)(x-1) |
| (x-1)2 |
| x-1 |
| x+1 |
| 1-x |
| 1+x |
=
| 1-x |
| x+1 |
把x=
| 1 |
| 2 |
原式=
1-
| ||
|
| 1 |
| 3 |
点评:此题考查了分式的化简求值,用到的知识点是分式的乘除、约分,在计算时要注意运算顺序和符号.
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