题目内容
计算
(1)-
×(-2)3-[1-1÷(-2
)]÷
( 2)-12-[1
+(-12)÷6]2×(-
)3
(3){0.85-[12+4×(3-10)]}÷5
(4)22+(-2)3×5-(-0.28)÷(-2)2.
(1)-
| 1 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
( 2)-12-[1
| 3 |
| 7 |
| 3 |
| 4 |
(3){0.85-[12+4×(3-10)]}÷5
(4)22+(-2)3×5-(-0.28)÷(-2)2.
(1)-
×(-2)3-[1-1÷(-2
)]÷
=-
×(-8)-[1+
]÷
=2-
÷
=2-1.5
=0.5;
( 2)-12-[1
+(-12)÷6]2×(-
)3
=-1-[1
-2]2×(-
)
=-1-[-
]2×(-
)
=-1-
×(-
)
=-1+
=-
;
(3){0.85-[12+4×(3-10)]}÷5
={0.85-[12+4×(-7)]}÷5
={0.85-[12-28]}÷5
={0.85+16}÷5
=16.85÷5
=3.37;
(4)22+(-2)3×5-(-0.28)÷(-2)2
=4+(-8)×5-(-0.28)÷4
=4-40+0.07
=-35.93.
| 1 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
=-
| 1 |
| 4 |
| 2 |
| 5 |
| 4 |
| 5 |
=2-
| 6 |
| 5 |
| 4 |
| 5 |
=2-1.5
=0.5;
( 2)-12-[1
| 3 |
| 7 |
| 3 |
| 4 |
=-1-[1
| 3 |
| 7 |
| 27 |
| 64 |
=-1-[-
| 4 |
| 7 |
| 27 |
| 64 |
=-1-
| 16 |
| 49 |
| 27 |
| 64 |
=-1+
| 27 |
| 196 |
=-
| 169 |
| 196 |
(3){0.85-[12+4×(3-10)]}÷5
={0.85-[12+4×(-7)]}÷5
={0.85-[12-28]}÷5
={0.85+16}÷5
=16.85÷5
=3.37;
(4)22+(-2)3×5-(-0.28)÷(-2)2
=4+(-8)×5-(-0.28)÷4
=4-40+0.07
=-35.93.
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