题目内容
化简,求值:| m2-2m+1 |
| m2-1 |
| m-1 |
| m+1 |
| 3 |
分析:先根据分式的混合运算法则把分式化简,再把m=
代入求解即可求得答案.
| 3 |
解答:解:原式=
÷
,
=
•
,
=
•
,
=
,
=
,
=
.
∴当m=
时,原式=
=
.
| m2-2m+1 |
| m2-1 |
| (m-1)(m+1)-(m-1) |
| m+1 |
=
| (m-1)2 |
| (m-1)(m+1) |
| m+1 |
| m2-1-m+1 |
=
| m-1 |
| m+1 |
| m+1 |
| m2-m |
=
| m-1 |
| m2-m |
=
| m-1 |
| m(m-1) |
=
| 1 |
| m |
∴当m=
| 3 |
| 1 | ||
|
| ||
| 3 |
点评:此题考查了分式的化简求值问题.解题的关键是先将利用分式的混合运算法则化简分式.
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