题目内容
计算:
(1)
-
(2)
÷(a-
).
(1)
| 1 |
| x |
| 1 |
| x-y |
(2)
| a-1 |
| a |
| 2a-1 |
| a |
分析:(1)先通分,再把分子相加减即可;
(2)根据分式混合运算的法则进行计算即可.
(2)根据分式混合运算的法则进行计算即可.
解答:解:(1)原式=
-
=
=-
;
(2)原式=
÷
=
•
=
.
| x-y |
| x(x-y) |
| x |
| x(x-y) |
=
| x-y-x |
| x(x-y) |
=-
| y |
| x(x-y) |
(2)原式=
| a-1 |
| a |
| (a-1)2 |
| a |
=
| a-1 |
| a |
| a |
| (a-1)2 |
=
| 1 |
| a-1 |
点评:本题考查的是分式的混合运算,熟知分式混合运算的法则是解答此题的关键.
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