题目内容
计算:(1)
-
÷
(2)
÷(
-x-2)
| 1 |
| x+2 |
| x2+2x+1 |
| x+2 |
| x2-1 |
| x-1 |
| 3-x |
| x-2 |
| 5 |
| x-2 |
分析:(1)将除法转化为乘法,分子、分母因式分解,约分,再通分;
(2)括号里先通分,再将除法转化为乘法,约分.
(2)括号里先通分,再将除法转化为乘法,约分.
解答:解:(1)原式=
-
•
=
-
=-
;
(2)原式=
÷
=
•
=
.
| 1 |
| x+2 |
| (x+1)2 |
| x+2 |
| x-1 |
| (x+1)(x-1) |
| 1 |
| x+2 |
| x+1 |
| x+2 |
| x |
| x+2 |
(2)原式=
| 3-x |
| x-2 |
| 5-(x+2)(x-2) |
| x-2 |
| 3-x |
| x-2 |
| x-2 |
| (3+x)(3-x) |
| 1 |
| x+3 |
点评:本题考查分式的混合运算,关键是通分,合并同类项,注意混合运算的运算顺序.
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