题目内容
先化简再求值:| x2+2x+1 |
| x2-1 |
| x |
| x-1 |
分析:本题的关键是正确进行分式的通分、约分,并准确代值计算.
解答:解:
-
=
-
=
;
当x=2时,原式=
=1.
| x2+2x+1 |
| x2-1 |
| x |
| x-1 |
| x+1 |
| x-1 |
| x |
| x-1 |
| 1 |
| x-1 |
当x=2时,原式=
| 1 |
| x-1 |
点评:本题主要考查分式的化简求值,把分式化到最简是解答的关键.
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