题目内容
计算题:(1)(-12)÷4×(-6)÷2
(2)(-
| 5 |
| 8 |
(3)(-1
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 4 |
(4)(-3)3÷2
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 3 |
分析:(1)直接运用同级运算按从左到右的顺序计算;
(2)和(4)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(3)先去括号,把加减法统一成加法,再运用运算律简便运算.
(2)和(4)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(3)先去括号,把加减法统一成加法,再运用运算律简便运算.
解答:解:(1)(-12)÷4×(-6)÷2=(-12)×
×(-6)×
=9.
(2)(-
)×(-4)2-0.25×(-5)×(-4)3
=-
×16-0.25×(-4)×(-5)×(-4)2=-10-80=-90.
(3)(-1
)-1
+(-2
)-(-3
)-(-1
)
=-1
-1
-2
+3
+1
=(-1
+1
)+(-1
-2
)+3
=0-4+3
=-
.
(4)(-3)3÷2
×(-
)2+4-22×(-
)
=-27×
×
+4-4×(-
)
=-
+4+
=0.
| 1 |
| 4 |
| 1 |
| 2 |
(2)(-
| 5 |
| 8 |
=-
| 5 |
| 8 |
(3)(-1
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 4 |
=-1
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 4 |
=(-1
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 4 |
(4)(-3)3÷2
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 3 |
=-27×
| 4 |
| 9 |
| 4 |
| 9 |
| 1 |
| 3 |
=-
| 16 |
| 3 |
| 4 |
| 3 |
点评:本题考查的是有理数的运算能力.要正确掌握运算顺序,即乘方运算(和以后学习的开方运算)叫做三级运算;乘法和除法叫做二级运算;加法和减法叫做一级运算.在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序.注意要会灵活运用法则或者运算律进行解题.
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