题目内容
化简:| x-y |
| x+3y |
| x2+6xy+9y2 |
| x2-y2 |
| 2y |
| x+y |
分析:首先分母分子能因式分解的先因式分解,然后进行约分,最后进行加减运算.
解答:解:原式=
•
-
=
•
-
=
-
=
=1.
| x-y |
| x+3y |
| x2+6xy+9y2 |
| x2-y2 |
| 2y |
| x+y |
=
| x-y |
| x+3y |
| (x+3y)2 |
| (x+y)(x-y) |
| 2y |
| x+y |
=
| x+3y |
| x+y |
| 2y |
| x+y |
=
| x+y |
| x+y |
点评:本题主要考查分式的混合运算,注意运算顺序,约分是解题的关键.
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