题目内容
计算(
+
)÷
．
| a+1 |
| a2-a |
| 4 |
| 1-a2 |
| a-1 |
| a2+2a+1 |
原式=[
-
]•
=
•
=
•
=
．
| a+1 |
| a(a-1) |
| 4 |
| (a+1)(a-1) |
| (a+1)2 |
| a-1 |
=
| (a+1)2-4a |
| a(a+1)(a-1) |
| (a+1)2 |
| a-1 |
=
| (a-1)2 |
| a(a+1)(a-1) |
| (a+1)2 |
| a-1 |
| a+1 |
| a |
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