题目内容
用配方法解方程:2t2-6t+3=0.
移项、系数化为1得,t2-3t=-
配方得t2-3t+
=-
+
,
即(t-
)2=
,
开方得t-
=±
,
∴x1=
,x2=
.
| 3 |
| 2 |
配方得t2-3t+
| 9 |
| 4 |
| 3 |
| 2 |
| 9 |
| 4 |
即(t-
| 3 |
| 2 |
| 3 |
| 4 |
开方得t-
| 3 |
| 2 |
| ||
| 2 |
∴x1=
3+
| ||
| 2 |
3-
| ||
| 2 |
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| 3 |
| 2 |
| 9 |
| 4 |
| 3 |
| 2 |
| 9 |
| 4 |
| 3 |
| 2 |
| 3 |
| 4 |
| 3 |
| 2 |
| ||
| 2 |
3+
| ||
| 2 |
3-
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| 2 |