题目内容
14.方程组$\left\{\begin{array}{l}{x+2y=5}\\{3x-2y=-1}\end{array}\right.$的解为$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$.分析 方程组利用加减消元法求出解即可.
解答 解:$\left\{\begin{array}{l}{x+2y=5①}\\{3x-2y=-1②}\end{array}\right.$,
①+②得:4x=4,
解得:x=1,
将x=1代入①得:y=2,
则方程组的解为$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$.
点评 此题考查了解二元一次方程组,利用了消元的思想,消元的方法有:代入消元法与加减消元法.
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