题目内容
计算:
(1)(-12a2b2c)•(-
abc2)2=______;
(2)(3a2b-4ab2-5ab-1)•(-2ab2)=______.
(1)(-12a2b2c)•(-
| 1 |
| 4 |
(2)(3a2b-4ab2-5ab-1)•(-2ab2)=______.
(1)(-12a2b2c)•(-
abc2)2,
=(-12a2b2c)•
a2b2c4,
=-
a4b4c5;
故答案为:-
a4b4c5;
(2)(3a2b-4ab2-5ab-1)•(-2ab2),
=3a2b•(-2ab2)-4ab2•(-2ab2)-5ab•(-2ab2)-1•(-2ab2),
=-6a3b3+8a2b4+10a2b3+2ab2.
故答案为:-6a3b3+8a2b4+10a2b3+2ab2.
| 1 |
| 4 |
=(-12a2b2c)•
| 1 |
| 16 |
=-
| 3 |
| 4 |
故答案为:-
| 3 |
| 4 |
(2)(3a2b-4ab2-5ab-1)•(-2ab2),
=3a2b•(-2ab2)-4ab2•(-2ab2)-5ab•(-2ab2)-1•(-2ab2),
=-6a3b3+8a2b4+10a2b3+2ab2.
故答案为:-6a3b3+8a2b4+10a2b3+2ab2.
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