题目内容

计算:
(1)(-12a2b2c)•(-
1
4
abc22=______;
(2)(3a2b-4ab2-5ab-1)•(-2ab2)=______.
(1)(-12a2b2c)•(-
1
4
abc22
=(-12a2b2c)•
1
16
a2b2c4

=-
3
4
a4b4c5

故答案为:-
3
4
a4b4c5

(2)(3a2b-4ab2-5ab-1)•(-2ab2),
=3a2b•(-2ab2)-4ab2•(-2ab2)-5ab•(-2ab2)-1•(-2ab2),
=-6a3b3+8a2b4+10a2b3+2ab2
故答案为:-6a3b3+8a2b4+10a2b3+2ab2
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