题目内容
已知| a-1 |
| 1 |
| ab |
| 1 |
| (a+1)(b+1) |
| 1 |
| (a+2)(b+2) |
| 1 |
| (a+2004)(b+2004) |
分析:由
+(ab-2)2=0,可求出a=1,b=2,代入所求分式,根据
=
-
,化简即可得出答案.
| a-1 |
| 1 |
| n(n+1) |
| 1 |
| n |
| 1 |
| n+1 |
解答:解:由
+(ab-2)2=0,可求出a=1,b=2,代入得:
+
+
+…+
=1-
+
-
+
-
+…+
-
=1-
=
.
| a-1 |
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 2005×2006 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2005 |
| 1 |
| 2006 |
=1-
| 1 |
| 2006 |
=
| 2005 |
| 2006 |
点评:本题考查了分式的化简求值,难度适中,关键是
=
-
公式的运用.
| 1 |
| n(n+1) |
| 1 |
| n |
| 1 |
| n+1 |
练习册系列答案
相关题目