题目内容
将下列各式通分:
,
,
.
| n |
| m2+2mn |
| m |
| 2n2-mn |
| mn |
| m2-4n2 |
考点:通分
专题:
分析:先分解因式,再找出公因式通分即可.
解答:解:
=
=
,
=
=
,
=
.
| n |
| m2+2mn |
| n |
| m(2n+m) |
| n2(2n-m) |
| mn(2n+m)(2n-m) |
| m |
| 2n2-mn |
| m |
| n(2n-m) |
| m2(2n+m) |
| mn(2n+m)(2n-m) |
| mn |
| m2-4n2 |
| -m2n2 |
| mn(m+2n)(2n-m) |
点评:本题主要考查了通分,解题的关键是正确找出公分母.
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