题目内容
化简| 2 |
| x2-4 |
| 1 |
| 2x-4 |
分析:先把原式的分母通分,化为同分母的分数后再相加减.
解答:解:原式=
-
=
=
=-
.
| 2 |
| (x+2)(x-2) |
| 1 |
| 2(x-2) |
=
| 4-(x+2) |
| 2(x+2)(x-2) |
=
| 2-x |
| 2(x+2)(x-2) |
=-
| 1 |
| 2(x+2) |
点评:本题考查了分式的加减法,要牢记异分母分式加减法法则:把分母不相同的几个分式化成分母相同的分式,叫做通分,经过通分,异分母分式的加减就转化为同分母分式的加减.:
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