题目内容
2.| A. | $\left\{\begin{array}{l}{x:y=7:5}\\{2(x+y)+4=52}\end{array}\right.$ | B. | $\left\{\begin{array}{l}{x:y=5:7}\\{2(x+y)+4=52}\end{array}\right.$ | ||
| C. | $\left\{\begin{array}{l}{x:y=5:7}\\{x+y=52}\end{array}\right.$ | D. | $\left\{\begin{array}{l}{x:y=7:5}\\{2(x+y)=52}\end{array}\right.$ |
分析 设小矩形的长为x,宽为y,根据题意列方程组解答即可.
解答 解:设小矩形的长为x,宽为y,可得:
$\left\{\begin{array}{l}{x:y=7:5}\\{2(x+y)+4=52}\end{array}\right.$,
故选A
点评 本题主要考查根据实际问题列方程组的能力,将未知量根据相等关系转化为方程是解题的关键.
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