题目内容
对于正数x,规定f(x)=
,如f(1)=
=
(1)计算f(2)=______;f(
)=______;f(2)+f(
)=______.f(3)+f(
)=______
(2)猜想f(x)+f(
)=______;请予以证明.
(3)现在你会计算f(
)+f(
)+f(
)+f(
)+f(
)+…f(
)+f(
)+f(1)+f(2)+f(3)+…+f(2007)+f(2008)+f(2009)+f(2010)+f(2011)的值了吗,写出你的计算过程.
| x2 |
| 1+x2 |
| 1 |
| 1+1 |
| 1 |
| 2 |
(1)计算f(2)=______;f(
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
(2)猜想f(x)+f(
| 1 |
| x |
(3)现在你会计算f(
| 1 |
| 2011 |
| 1 |
| 2010 |
| 1 |
| 2009 |
| 1 |
| 2008 |
| 1 |
| 2007 |
| 1 |
| 3 |
| 1 |
| 2 |
(1)∵f(x)=
,
∴f(2)=
=
,
f(
)=
=
,
f(2)+f(
)=
+
=1
f(3)+f(
)=
+
=
+
=1;
(2):猜想f(x)+f(
)=1,
证明如下:∵f(x)=
,
∴
,
∴f(x)+f(
)=
+
=1;
(3)f(
)+f(
)+f(
)+f(
)+f(
)+…f(
)+f(
)+f(1)+f(2)+f(3)+…+f(2007)+f(2008)+f(2009)+f(2010)+f(2011)
=f(
)+f(2011)+f(
)+f(2010)+…+f(
)+f(2)+f(1)
=1+1+…+1+
=2010
.
故答案为:
,
,1,1,1.
| x2 |
| 1+x2 |
∴f(2)=
| 22 |
| 1+22 |
| 4 |
| 5 |
f(
| 1 |
| 2 |
(
| ||
1+(
|
| 1 |
| 5 |
f(2)+f(
| 1 |
| 2 |
| 4 |
| 5 |
| 1 |
| 5 |
f(3)+f(
| 1 |
| 3 |
| 32 |
| 1+32 |
(
| ||
1+(
|
| 9 |
| 10 |
| 1 |
| 10 |
(2):猜想f(x)+f(
| 1 |
| x |
证明如下:∵f(x)=
| x2 |
| 1+x2 |
∴
|
∴f(x)+f(
| 1 |
| x |
| x2 |
| 1+x2 |
| 1 |
| x2+1 |
(3)f(
| 1 |
| 2011 |
| 1 |
| 2010 |
| 1 |
| 2009 |
| 1 |
| 2008 |
| 1 |
| 2007 |
| 1 |
| 3 |
| 1 |
| 2 |
=f(
| 1 |
| 2011 |
| 1 |
| 2010 |
| 1 |
| 2 |
=1+1+…+1+
| 1 |
| 2 |
=2010
| 1 |
| 2 |
故答案为:
| 4 |
| 5 |
| 1 |
| 5 |
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