题目内容
化简:(
-
)÷
.
| 1 |
| x+1 |
| 1 |
| x-1 |
| 2 |
| x2-1 |
分析:首先对括号内的分式进行通分相减,然后把除法转化为乘法,进行约分即可.
解答:解:原式=【
-
】•
=
•
=-1
| x-1 |
| (x+1)(x-1) |
| x+1 |
| (x+1)(x-1) |
| (x+1)(x-1) |
| 2 |
=
| -2 |
| (x+1)(x-1) |
| (x+1)(x-1) |
| 2 |
=-1
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
练习册系列答案
相关题目