题目内容
计算
(1)(
-
-
)×(-24)
(2)-14-
×[3-(-3)2].
(1)(
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
(2)-14-
| 1 |
| 6 |
考点:有理数的混合运算
专题:
分析:(1)利用乘法分配律简算;
(2)先算乘方,再算括号里面的减法,再算乘法,最后算减法.
(2)先算乘方,再算括号里面的减法,再算乘法,最后算减法.
解答:解:(1)(
-
-
)×(-24)
=
×(-24)-
×(-24)-
×(-24)
=-9+4+18
=13;
(2)-14-
×[3-(-3)2]
=-1-
×[3-9]
=-1-
×(-6)
=-1+1
=0.
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=-9+4+18
=13;
(2)-14-
| 1 |
| 6 |
=-1-
| 1 |
| 6 |
=-1-
| 1 |
| 6 |
=-1+1
=0.
点评:此题考查有理数的混合运算,注意运算顺序与运算符号的判定.
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