题目内容
先化简代数式
÷(x-1-
)，然后选取一个你喜欢的数代入，求原代数式的值．
| x2-2x |
| x2-1 |
| 2x-1 |
| x+1 |
| x2-2x |
| x2-1 |
| 2x-1 |
| x+1 |
=
| x(x-2) |
| (x-1)(x+1) |
| (x-1)(x+1) |
| x+1 |
| 2x-1 |
| x+1 |
=
| x(x-2) |
| (x-1)(x+1) |
| x2-1-2x+1 |
| x+1 |
=
| x(x-2) |
| (x-1)(x+1) |
| x+1 |
| x(x-2) |
=
| 1 |
| x-1 |
只要x≠1，-1，2，随便取一个数代入即可；
当x=3时，
原式=
| 1 |
| x-1 |
| 1 |
| 2 |
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