题目内容

计算:
(1)
a
a-b
+
b
b-a
        
(2)(
a2b
-cd3
3÷
2a
d3
-
c
2a
2          
(3)
a2
a-1
-a-1
(1)原式=
a
a-b
-
b
a-b
=
a-b
a-b
=1;
(2)原式=-
a6b3
c3d9
d3
2a
-
c2
4a2
=
a5b3
2c3d6
-
c2
4a2
=
2a7b3-c3d6
4a2c3d6

(3)原式=
a2
a-1
-
(a+1)(a-1)
a-1
=
a2-(a2-1)
a-1
=
1
a-1
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