题目内容
计算:| 2x |
| x+y |
| x-y |
| x+y |
分析:根据同分母的分式的加减运算法则求解即可求得答案,注意结果要化为最简.
解答:解:
-
=
=
=1.
故答案为:1.
| 2x |
| x+y |
| x-y |
| x+y |
| 2x-x+y |
| x+y |
| x+y |
| x+y |
故答案为:1.
点评:此题考查了同分母分式的加减运算法则.此题比较简单,解题需细心,注意结果要化为最简.
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计算:| 2x |
| x+y |
| x-y |
| x+y |
| 2x |
| x+y |
| x-y |
| x+y |
| 2x-x+y |
| x+y |
| x+y |
| x+y |