题目内容
化简求值:
(1)求5(3a2b-ab2)-4(-ab2+3a2b)的值,其中a=
,b=-
;
(2)若2x2-3x+1=0,求代数式5x2-[5x2-4x2+2x+4x-5]的值.
(1)求5(3a2b-ab2)-4(-ab2+3a2b)的值,其中a=
| 1 |
| 2 |
| 1 |
| 3 |
(2)若2x2-3x+1=0,求代数式5x2-[5x2-4x2+2x+4x-5]的值.
(1)5(3a2b-ab2)-4(-ab2+3a2b),
=15a2b-5ab2+4ab2-12a2b,
=3a2b-ab2,
当a=
,b=-
时,
原式=3×
×(-
)-
×(-
)2,
=-
;
(2)5x2-[5x2-4x2+2x+4x-5],
=5x2-5x2+4x2-2x-4x+5,
=4x2-6x+5,
∵2x2-3x+1=0,
∴2x2-3x=-1,
∴4x2-6x=-2,
∴原式=-2+5=3.
=15a2b-5ab2+4ab2-12a2b,
=3a2b-ab2,
当a=
| 1 |
| 2 |
| 1 |
| 3 |
原式=3×
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
=-
| 11 |
| 36 |
(2)5x2-[5x2-4x2+2x+4x-5],
=5x2-5x2+4x2-2x-4x+5,
=4x2-6x+5,
∵2x2-3x+1=0,
∴2x2-3x=-1,
∴4x2-6x=-2,
∴原式=-2+5=3.
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