题目内容
计算:
(1)1
×[3×(-
)2-1];
(2)(-24)×(
-
+
).
(1)1
| 1 |
| 2 |
| 2 |
| 3 |
(2)(-24)×(
| 7 |
| 12 |
| 5 |
| 6 |
| 3 |
| 4 |
分析:(1)先算乘方,再算括号里面的乘法,再算括号里面的减法,最后算乘法;
(2)利用乘法分配律简算.
(2)利用乘法分配律简算.
解答:解:(1)原式=
×[3×
-1]
=
×[
-1]
=
×
=
;
(2)原式=(-24)×
-(-24)×
+(-24)×
=-14+20-18
=-12.
| 3 |
| 2 |
| 4 |
| 9 |
=
| 3 |
| 2 |
| 4 |
| 3 |
=
| 3 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 2 |
(2)原式=(-24)×
| 7 |
| 12 |
| 5 |
| 6 |
| 3 |
| 4 |
=-14+20-18
=-12.
点评:此题考查有理数的混合运算,注意运算顺序与运算定律的运用.
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