题目内容
若| 1-3x |
| x2-1 |
| M |
| x+1 |
| N |
| x-1 |
分析:先把等式左边通分,化为最简后再利用
=
+
求出M、N的值.
| 1-3x |
| x2-1 |
| M |
| x+1 |
| N |
| x-1 |
解答:解:
+
=
+
=
=
,
∴M+N=-3,N-M=1,
∴M=-2,N=-1,
故答案为-2,-1.
| M |
| x+1 |
| N |
| x-1 |
| M(x-1) |
| (x+1)(x-1) |
| N(x+1) |
| (x+1)(x-1) |
| (M+N)x+(N-M) |
| x2-1 |
| 1-3x |
| x2-1 |
∴M+N=-3,N-M=1,
∴M=-2,N=-1,
故答案为-2,-1.
点评:本题考查了分式的加减法法则,异分母分式加减法,把分母不相同的几个分式化成分母相同的分式,叫做通分,经过通分,异分母分式的加减就转化为同分母分式的加减.
练习册系列答案
相关题目