题目内容
先化简,再求值:| x2-2x |
| x2-1 |
| 2x-1 |
| x+1 |
| 1 |
| 2 |
分析:先通分,然后进行四则运算,最后将x=
代入.
| 1 |
| 2 |
解答:解:原式=
÷
=
×
=
.
∵x=
,
∴原式=
=
=-2.
| x(x-2) |
| (x+1)(x-1) |
| (x+1)(x-1)-(2x-1) |
| x+1 |
=
| x(x-2) |
| (x+1)(x-1) |
| x+1 |
| x(x-2) |
=
| 1 |
| x-1 |
∵x=
| 1 |
| 2 |
∴原式=
| 1 |
| x-1 |
| 1 | ||
|
点评:本题主要考查分式的化简求值的知识点,解答本题的关键是把两分式合并后约分最简,本题难度一般,代值计算要仔细.
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