题目内容
已知
=
,则
÷
=
.
| y |
| x |
| 3 |
| 2 |
| x2-y2 |
| x2-2xy+y2 |
| xy+y2 |
| x2-xy |
| 2 |
| 3 |
| 2 |
| 3 |
分析:先根据分式混合运算的法则把原式化简,再把
=
代入进行计算即可.
| y |
| x |
| 3 |
| 2 |
解答:解:原式=
×
=
,
∵
=
,
∴
=
.
故答案为:
.
| (x+y)(x-y) |
| (x-y)2 |
| x(x-y) |
| y(x+y) |
=
| x |
| y |
∵
| y |
| x |
| 3 |
| 2 |
∴
| x |
| y |
| 2 |
| 3 |
故答案为:
| 2 |
| 3 |
点评:本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.
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