题目内容
(1)已知
=
,则
=______;(2)已知
=
,则
=______.
| a |
| b |
| 3 |
| 2 |
| a-b |
| b |
| y |
| x+2y |
| 1 |
| 4 |
| x |
| y |
(1)∵
=
,∴a=
b,∴原式=
=
;
(2)∵
=
,∴x=2y,∴
=2.
故答案为:
,2.
| a |
| b |
| 3 |
| 2 |
| 3 |
| 2 |
| ||
| b |
| 1 |
| 2 |
(2)∵
| y |
| x+2y |
| 1 |
| 4 |
| x |
| y |
故答案为:
| 1 |
| 2 |
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