题目内容
计算:(2xy-y)-(-y+xy)=
x)=
xy
xy
;-3×(1-| 1 |
| 6 |
-3+
x
| 1 |
| 2 |
-3+
x
.| 1 |
| 2 |
分析:去括号后合并同类项即可,根据乘法分配律展开即可.
解答:解:(2xy-y)-(-y+xy)
=2xy-y+y-xy
=xy;
-3×(1-
x)
=-3+
x.
故答案为:xy;-3+
x.
=2xy-y+y-xy
=xy;
-3×(1-
| 1 |
| 6 |
=-3+
| 1 |
| 2 |
故答案为:xy;-3+
| 1 |
| 2 |
点评:本题考查了整式的化简的应用,主要考查学生的化简能力.
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