题目内容
已知xy=5,a-b=
,a+b=
,则xya2-xyb2=______.
| 2 |
| 3 |
| 3 |
| 10 |
xya2-xyb2=xy(a2-b2),
=xy(a+b)(a-b),
∵xy=5,a-b=
,a+b=
,
∴原式=5×
×
=1.
故答案为:1.
=xy(a+b)(a-b),
∵xy=5,a-b=
| 2 |
| 3 |
| 3 |
| 10 |
∴原式=5×
| 2 |
| 3 |
| 3 |
| 10 |
故答案为:1.
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