题目内容


若不等式组有实数解,则实数m的取值范围是(  )              

A.m≤                       B.m<                     C.m>                     D.m≥


A【考点】解一元一次不等式组.                                                            

【专题】压轴题.                                                                              

【分析】解出不等式组的解集,根据不等式组有实数解,可以求出实数m的取值范围.              

【解答】解:解5﹣3x≥0,得x≤;                                                        

解x﹣m≥0,得x≥m,                                                                        

∵不等式组有实数解,                                                                       

∴m≤.                                                                                           

故选A.                                                                                            

【点评】本题是反向考查不等式组的解集,也就是在不等式组有实数解的情况下确定不等式中字母的取值范围,解答本题时,易忽略m=,当m=时,不等式组的解集是x=.                                

                                                                                                       


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