题目内容


在△ABC中,∠C=90°,AC=1,AB=3,则cosB=      .                    


 .                                                                                           

【考点】锐角三角函数的定义.                                                              

【分析】先画出图形,根据勾股定理和余弦函数的定义解答.                        

【解答】解:如图:                                                                          

在△ABC中,∠C=90°,AC=1,AB=3,                                                  

由勾股定理可得:BC=2,                                                                   

∴cosB==.                                                                            

                                                                           

【点评】本题考查锐角三角函数的定义及运用:在直角三角形中,锐角的正弦为对边比斜边,余弦为邻边比斜边,正切为对边比边.                                                                                        

                                                                                                       


练习册系列答案
相关题目

为了让学生了解环保知识,增强环保意识,某中学举行了一次“环保知识竞赛”,共有850名学生参加了这次竞赛,为了解本次竞赛成绩情况,从中抽取了部分学生的成绩(得分取整数,满分为100分)进行统计.请你根据尚未完成并有局部污染的频率分布表和频率分布直方图,解答下列问题:                                             

分   组                频数        频率

50.5~60.5            4              0.08

60.5~70.5                           0.16

70.5~80.5            10           

80.5~90.5            16            0.32

90.5~100.5                         

合   计                50            1.00

(1)填充频率分布表的空格;                                                                

(2)补全频数直方图,并在此图上直接绘制频数分布折线图;                      

(3)全体参赛学生中,竞赛成绩落在哪组范围内的人数最多?                     

(4)若成绩在90分以上(不含90分)为优秀,则该校成绩优秀的约为多少人?               

                                         

                                                                                                       

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网