题目内容

18.若方程mx+ny=6的两个解是$\left\{\begin{array}{l}{x=1}\\{y=1}\end{array}\right.$,$\left\{\begin{array}{l}{x=2}\\{y=-1}\end{array}\right.$,则m,n的值为(  )
A.$\left\{\begin{array}{l}{m=4}\\{n=2}\end{array}\right.$B.$\left\{\begin{array}{l}{m=2}\\{n=4}\end{array}\right.$C.$\left\{\begin{array}{l}{m=-2}\\{n=-4}\end{array}\right.$D.$\left\{\begin{array}{l}{m=-4}\\{n=-2}\end{array}\right.$

分析 把x与y的两对值代入方程求出m与n的值即可.

解答 解:根据题意得:$\left\{\begin{array}{l}{m+n=6①}\\{2m-n=6②}\end{array}\right.$,
①+②得:3m=12,
解得:m=4,
把m=4代入①得:n=2,
则方程组的解为$\left\{\begin{array}{l}{m=4}\\{n=2}\end{array}\right.$,
故选A

点评 此题考查了二元一次方程的解,方程的解即为能使方程左右两边相等的未知数的值.

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