题目内容
已知0<a<1,化简a+
|
a+
|
分析:因为a=(
)2,
=
,又0<a<1,所以(
)2<
,即
<
.
| a |
| 1 |
| a |
| 1 | ||
(
|
| a |
| 1 | ||
(
|
| a |
| 1 | ||
|
解答:解:∵0<a<1,
∴
<
,
∴原式=
-
=
-
=
+
-(
-
)=2
.
∴
| a |
| 1 | ||
|
∴原式=
(
|
(
|
=
(
|
(
|
=
| a |
| 1 | ||
|
| 1 | ||
|
| a |
| a |
点评:注意当x<0时,
=-x.
| x2 |
练习册系列答案
相关题目