题目内容
观察下列等式:
=1-
,
=
-
,
=
-
,将以上三个等式相加得:
+
+
=1-
+
-
+
-
=1-
=
.
(1)猜想并写出:
=______.
(2)直接写出结果:
+
+
+…+
=______.
| 1 |
| 1×2 |
| 1 |
| 2 |
| 1 |
| 2×3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3×4 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 4 |
(1)猜想并写出:
| 1 |
| n(n+1) |
(2)直接写出结果:
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 2006×2007 |
(1)根据题中的一系列等式,可得
=
-
;
(2)
+
+
+…+
=1-
+
-
+
-
+…+
-
=1-
=
.
故答案为:(1)
-
;(2)
| 1 |
| n(n+1) |
| 1 |
| n |
| 1 |
| n+1 |
(2)
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 2006×2007 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2006 |
| 1 |
| 2007 |
| 1 |
| 2007 |
| 2006 |
| 2007 |
故答案为:(1)
| 1 |
| n |
| 1 |
| n+1 |
| 2006 |
| 2007 |
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