题目内容
计算与化简
(1)(-
)-(-3
)+(+2
)-(+5
)
(2)-22+|5-8|+24÷(-3)×
(3)-2
×5-2
×(-4)+
×(-8)
(4)1-
×[3×(-
)2-(-1)4]+
÷(-
)3
(5)4x3-[-x2-2(x3-
x2+1)]
(6)4ab-3b2-[(a2+b2)-(a2-b2)].
(1)(-
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 2 |
(2)-22+|5-8|+24÷(-3)×
| 1 |
| 3 |
(3)-2
| 1 |
| 6 |
| 1 |
| 6 |
| 13 |
| 6 |
(4)1-
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
(5)4x3-[-x2-2(x3-
| 1 |
| 2 |
(6)4ab-3b2-[(a2+b2)-(a2-b2)].
分析:(1)先算同分母分数,再相加即可;
(2)(4)(5)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(3)直接运用乘法的分配律计算;
(6)运用整式的加减运算顺序,先去括号,再合并同类项.
(2)(4)(5)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(3)直接运用乘法的分配律计算;
(6)运用整式的加减运算顺序,先去括号,再合并同类项.
解答:解:(1)(-
)-(-3
)+(+2
)-(+5
)
=(-
-5
)+(3
+2
)
=-6+6
=0;
(2)-22+|5-8|+24÷(-3)×
=-4+3-8×
=-4+3-2
=-3
;
(3)-2
×5-2
×(-4)+
×(-8)
=-
×(5-4+8)
=-
×9
=-19.5;
(4)1-
×[3×(-
)2-(-1)4]+
÷(-
)3
=1-
×[3×
-1]+
÷(-
)
=1-
×[
-1]-2
=1-
×
-2
=1-
-2
=-1
;
(5)4x3-[-x2-2(x3-
x2+1)]
=4x3-[-x2-2x3+x2-2]
=4x3+x2+2x3-x2+2
=6x3+2;
(6)4ab-3b2-[(a2+b2)-(a2-b2)]
=4ab-3b2-[a2+b2-a2+b2]
=4ab-3b2-2b2
=4ab-5b2.
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 2 |
=(-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
=-6+6
=0;
(2)-22+|5-8|+24÷(-3)×
| 1 |
| 3 |
=-4+3-8×
| 1 |
| 3 |
=-4+3-2
| 2 |
| 3 |
=-3
| 2 |
| 3 |
(3)-2
| 1 |
| 6 |
| 1 |
| 6 |
| 13 |
| 6 |
=-
| 13 |
| 6 |
=-
| 13 |
| 6 |
=-19.5;
(4)1-
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
=1-
| 1 |
| 2 |
| 4 |
| 9 |
| 1 |
| 4 |
| 1 |
| 8 |
=1-
| 1 |
| 2 |
| 4 |
| 3 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
=1-
| 1 |
| 6 |
=-1
| 1 |
| 6 |
(5)4x3-[-x2-2(x3-
| 1 |
| 2 |
=4x3-[-x2-2x3+x2-2]
=4x3+x2+2x3-x2+2
=6x3+2;
(6)4ab-3b2-[(a2+b2)-(a2-b2)]
=4ab-3b2-[a2+b2-a2+b2]
=4ab-3b2-2b2
=4ab-5b2.
点评:本题考查的是有理数的运算能力.注意:
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
(3)整式中如果有多重括号应按照先去小括号,再去中括号,最后大括号的顺序进行.
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
(3)整式中如果有多重括号应按照先去小括号,再去中括号,最后大括号的顺序进行.
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