题目内容
当x=-
时,求(
-
)÷
的值.
| 1 |
| 3 |
| 3x |
| x-1 |
| x |
| x+1 |
| x |
| x2-1 |
原式=
×
,
=
×
,
=2x+4,
当x=-
时,原式=2×(-
)+4,
=
.
| 3x(x+1)-x(x-1) |
| (x-1)(x+1) |
| (x+1)(x-1) |
| x |
=
| 3x2+3x-x2+x |
| (x+1)(x-1) |
| (x+1)(x-1) |
| x |
=2x+4,
当x=-
| 1 |
| 3 |
| 1 |
| 3 |
=
| 10 |
| 3 |
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