题目内容
先化简,再选择你喜欢的又使原式有意义的一个x的值代入求值.(| 1 |
| x-1 |
| x+1 |
| 1-x |
| x |
| x-1 |
分析:先把分式(
+
)÷(x+
)进行通分,将除法变为乘法,约分化简为最简分式,然后把符合要求的x的值代入计算即可.
| 1 |
| x-1 |
| x+1 |
| 1-x |
| x |
| x-1 |
解答:解:(
+
)÷(x+
)
=
÷
=
•
=-
,
当x=2时,原式=-
.
| 1 |
| x-1 |
| x+1 |
| 1-x |
| x |
| x-1 |
=
| 1-x-1 |
| x-1 |
| x(x-1+1) |
| x-1 |
=
| -x |
| x-1 |
| x-1 |
| x2 |
=-
| 1 |
| x |
当x=2时,原式=-
| 1 |
| 2 |
点评:本题考查了分式的化简求值,难度不大,关键是把已知分式化为最简分式的形式,然后代入求值.
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