题目内容
8.解方程组$\left\{\begin{array}{l}{ax+by=6}\\{cx-4y=-2}\end{array}\right.$,小明正确解得$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$,小丽只看错了c解得$\left\{\begin{array}{l}{x=-2}\\{y=1}\end{array}\right.$,则当x=-1时,代数式ax2-bx+c的值为6.5.分析 把$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$代入方程组$\left\{\begin{array}{l}{ax+by=6}\\{cx-4y=-2}\end{array}\right.$得出$\left\{\begin{array}{l}{2a+3b=6①}\\{2c-12=-2②}\end{array}\right.$,求出c,把$\left\{\begin{array}{l}{x=-2}\\{y=1}\end{array}\right.$代入ax+by=6得出-2a+b=6③,由①和③组成方程组,求出a、b值,最后代入求出即可.
解答 解:把$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$代入方程组$\left\{\begin{array}{l}{ax+by=6}\\{cx-4y=-2}\end{array}\right.$得:$\left\{\begin{array}{l}{2a+3b=6①}\\{2c-12=-2②}\end{array}\right.$,
解②得:c=5,
把$\left\{\begin{array}{l}{x=-2}\\{y=1}\end{array}\right.$代入ax+by=6得:-2a+b=6③,
由①和③组成方程组$\left\{\begin{array}{l}{2a+3b=6}\\{-2a+b=6}\end{array}\right.$,
解得:a=-1.5,b=3,
当x=-1时,ax2-bx+c=-1.5×(-1)2-3×(-1)+5=6.5,
故答案为:6.5.
点评 本题考查了解二元一次方程组,二元一次方程组的解等知识点,能求出a、b、c的值是解此题的关键.
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