题目内容
若a、b、c为△ABC的三条边,化简
+
=______.
| (a+b-c)2 |
| (b-a-c)2 |
∵a、b、c为△ABC的三条边,
∴a+b>c,a+c>b,
∴a+b-c>0,b-a-c<0,
∴
+
,
=|a+b-c|+|b-a-c|,
=a+b-c-(b-a-c),
=a+b-c-b+a+c,
=2a.
故答案为:2a.
∴a+b>c,a+c>b,
∴a+b-c>0,b-a-c<0,
∴
| (a+b-c)2 |
| (b-a-c)2 |
=|a+b-c|+|b-a-c|,
=a+b-c-(b-a-c),
=a+b-c-b+a+c,
=2a.
故答案为:2a.
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