题目内容
计算:
(1)
÷(a-
);
(2)(x-y+
)(x+y-
).
(1)
| a-b |
| a |
| 2ab-b2 |
| a |
(2)(x-y+
| 4xy |
| x-y |
| 4xy |
| x+y |
考点:分式的混合运算
专题:
分析:按照通分算加减,进一步把分子或分母因式分解,约分算乘法得出答案即可.
解答:解:(1)原式=
÷
=
•
=
;
(2)原式=
•
=
•
=(x+y)(x-y)
=x2-y2.
| a-b |
| a |
| a2-2ab+b2 |
| a |
=
| a-b |
| a |
| a |
| (a-b)2 |
=
| 1 |
| a-b |
(2)原式=
| (x-y)2+4xy |
| x-y |
| (x+y)2-4xy |
| x+y |
=
| (x+y)2 |
| x-y |
| (x-y)2 |
| x+y |
=(x+y)(x-y)
=x2-y2.
点评:此题考查分式的混合运算,搞清运算顺序,通分、因式分解、约分是关键.
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