题目内容

计算:(1)(2x+1)(﹣2x+1)
(2)(2a﹣b22
(3)(3x+1)2(3x﹣1)2
(4)(x+1)(x2+1)(x4+1)(x﹣1)

解:(1)(2x+1)(﹣2x+1),
=12﹣(2x)2
=1﹣4x2
(2)(2a﹣b22
=4a2﹣2ab2+
(3)(3x+1)2(3x﹣1)2
=[(3x+1)(3x﹣1)]2
=(9x2﹣1)2,=81x4﹣18x2+1;
(4)(x+1)(x2+1)(x4+1)(x﹣1),
=(x+1)(x﹣1)(x2+1)(x4+1),
=(x2﹣1)(x2+1)(x4+1),
=(x4﹣1)(x4+1),
=x8﹣1
练习册系列答案
相关题目