题目内容
如果abc=1，求证
+
+
=1．
| 1 |
| ab+a+1 |
| 1 |
| bc+b+1 |
| 1 |
| ac+c+1 |
原式=
+
+
=
+
+
=
=1．
| 1 |
| ab+a+1 |
| a |
| abc+ab+a |
| ab |
| a2bc+abc+ab |
=
| 1 |
| ab+a+1 |
| a |
| 1+ab+a |
| ab |
| a+1+ab |
=
| ab+a+1 |
| ab+a+1 |
=1．
练习册系列答案
相关题目
+
+
=1．
+
+
=1．
+
+
=1．