Question

6£®ÔÚÒ»ÉÕ±­ÖÐÊ¢ÓÐ22.3g̼ËáÄƺÍÂÈ»¯ÄÆ×é³ÉµÄ¹ÌÌå»ìºÏÎ¼Ó×ãÁ¿Ë®Èܽ⣬ÖƳÉÈÜÒº£®ÏòÆäÖÐÖ𽥵μÓÈÜÖÊÖÊÁ¿·ÖÊýΪ10%µÄÏ¡ÑÎËᣬ·Å³öÆøÌåµÄ×ÜÖÊÁ¿ÓëËùµÎÈëÏ¡ÑÎËáµÄÖÊÁ¿¹ØϵÇúÏßÈçͼËùʾ£ºÇë¸ù¾ÝÌâÒâ»Ø´ðÎÊÌ⣺
£¨1£©Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºNa₂CO₃+2HCl¨T2NaCl+H₂O+CO₂¡ü£®
£¨2£©µ±µÎ¼ÓÁË73¿ËÏ¡ÑÎËáʱ£¬·Å³öÆøÌåµÄ×ÜÖÊÁ¿Îª4.4¿Ë£®
£¨3£©µ±µÎ¼ÓÏ¡ÑÎËáÖÁͼÖÐBµãʱ£¬ÉÕ±­ÖÐÈÜÒºÀïµÄÈÜÖÊÊÇNaClºÍHCl£¨Ð´»¯Ñ§Ê½£©£®
£¨4£©µ±µÎ¼ÓÁË73¿ËÏ¡ÑÎËáʱ£¨¼´Aµãʱ£©£¬ÉÕ±­ÖÐΪ²»±¥ºÍÈÜÒº£¬ÊÔͨ¹ý¼ÆËãÇó³öÆäÖÐËùº¬ÈÜÖʵÄÖÊÁ¿·ÖÊý£®

Answer 1

·ÖÎö £¨1£©¸ù¾Ý·´Ó¦ÎïÉú³ÉÎïÀ´ÕýÈ·Êéд»¯Ñ§·½³Ìʽ£»
£¨2£©ÓÉÌâÒâ¿ÉÒÔÖªµÀµÎ¼Ó73gÏ¡ÑÎËáʱÊÇÏ¡ÑÎËáºÍ̼ËáÄÆÇ¡ºÃÍêÈ«·´Ó¦µÄʱ¿Ì£¬¿ÉÒԾݴ˽áºÏÏ¡ÑÎËáµÄÖÊÁ¿½øÐÐÇó½â£»
£¨2£©´ÓͼÖпÉÒÔ¿´³öBµãʱϡÑÎËá¹ýÁ¿£¬ËùÒÔ´ËʱµÄÈÜÒºÖеÄÈÜÖÊΪÂÈ»¯ÄƺÍÂÈ»¯Ç⣬¿ÉÒԾݴ˽â´ð£»
£¨3£©¸ù¾Ý£¨1£©µÄ·ÖÎö¿ÉÒÔÖªµÀAµãΪϡÑÎËáºÍ̼ËáÄÆÇ¡ºÃÍêÈ«·´Ó¦µÄʱ¿Ì£¬ËùÒÔ¿ÉÒԾݴ˽áºÏÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿½øÐÐÇóË㣮

½â´ð ½â£º£¨1£©Ï¡ÑÎËáºÍ̼ËáÄÆÉú³ÉÂÈ»¯ÄƺÍË®ºÍ¶þÑõ»¯Ì¼£®
£¨2£©ÉèÔ­»ìºÏÎïÖк¬Ì¼ËáÄƵÄÖÊÁ¿Îªx£¬Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îªy£¬Éú³ÉÂÈ»¯ÄƵÄÖÊÁ¿Îªz
Na₂CO₃+2HCl¨T2NaCl+H₂O+CO₂¡ü
106     73     117     44
 x   73g¡Á10%   z       y
$\frac{106}{x}=\frac{73}{73g¡Á10%}=\frac{117}{z}=\frac{44}{y}$£¬
½âµÃ£ºx=10.6g y=4.4g z=11.7g
¹ÊÉú³ÉÆøÌåµÄÖÊÁ¿Îª4.4g£»
£¨3£©ÓÉͼʾ¿ÉÖª£¬µ±µÎ¼ÓÏ¡ÑÎËáÖÁͼÖÐAµãʱ£¬ÒÑÊÇÍêÈ«·´Ó¦£¬ÔٵμÓÏ¡ÑÎËáÖÁͼÖÐBµãʱ£¬ÑÎËá¾ÍÓÐÊ£Ó࣮¹ÊÈÜÒºÖеÄÈÜÖÊΪNaClºÍHCl£®
£¨4£©Ëùº¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ£º$\frac{11.7g+£¨22.3g-10.6g£©}{22.3g+73g-4.4g}¡Á100%$=25.7%£»
´ð£º£¨1£©Na₂CO₃+2HCl¨T2NaCl+H₂O+CO₂¡ü£»£¨2£©4.4£»£¨3£©NaClºÍHCl£»£¨4£©ÆäÖÐËùº¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ25.7%£®

µãÆÀ ±¾Ìâ½ÏºÃµÄ¿¼²éѧÉúÀûÓÃͼÏóÀ´·ÖÎö»¯Ñ§·´Ó¦µÄÄÜÁ¦£¬Ñ§ÉúÓ¦Ã÷ȷͼÏóÖеĹؼüµã¼°Ïߵı仯Ëù±íʾµÄº¬Ò壬½«Í¼ÏóºÍ»¯Ñ§·´Ó¦½ôÃܽáºÏÊǽâÌâµÄ¹Ø¼üËùÔÚ£®